hanie_kh
عضو جدید
سلام من یه فایل با پسوند php درست کردم که عکس هایی که توی یه پوشه هست رو میخونه ونشون میده و دکمه کپی داره .میخوام با کلیک روی این دکمه تابع copy()] اجرا بشه باید چی کار کنم؟سعی کردم از این دستور توی جاوا اسکریپت استفاده کنم اما نشد.
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
<script>
function y()
{ var x="<?php echo myphp() ?>";
alert(x);
}
</script>
</head>
<body>
<?php
$f=opendir("customer temp/");
while($a=readdir($f))
{if( is_file("customer temp/".$a))
{
echo "<img src='customer temp/".$a."' />";
// copy("customer temp/10930893_793147387432526_8349597862666589173_n.png","manager upload/pic1");
// echo $a."<br/>";
}
}
echo "<br/><br/>";
echo"<input type='button' onClick='y()' value='کپی'/>";
echo"<input type='button' onClick='del()' value='حذف'/>";
function myphp()
{if( is_dir("manager upload/"))
copy("customer temp/10930893_793147387432526_8349597862666589173_n.png","manager upload/pic1");
else
{ mkdir("manager upload");
copy("customer temp/10930893_793147387432526_8349597862666589173_n.png","manager upload/pic1");
}
}
?>
</body>
</html>
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Untitled Document</title>
<script>
function y()
{ var x="<?php echo myphp() ?>";
alert(x);
}
</script>
</head>
<body>
<?php
$f=opendir("customer temp/");
while($a=readdir($f))
{if( is_file("customer temp/".$a))
{
echo "<img src='customer temp/".$a."' />";
// copy("customer temp/10930893_793147387432526_8349597862666589173_n.png","manager upload/pic1");
// echo $a."<br/>";
}
}
echo "<br/><br/>";
echo"<input type='button' onClick='y()' value='کپی'/>";
echo"<input type='button' onClick='del()' value='حذف'/>";
function myphp()
{if( is_dir("manager upload/"))
copy("customer temp/10930893_793147387432526_8349597862666589173_n.png","manager upload/pic1");
else
{ mkdir("manager upload");
copy("customer temp/10930893_793147387432526_8349597862666589173_n.png","manager upload/pic1");
}
}
?>
</body>
</html>
